hi,
I've been looking everywhere to find an answer to this question, Basically, an equation is given
F(x)=3x(2-x)(x+1)(3+x)
What is the total local max and minimum value?
Please help me, my head is about to explode!! thank you!!
hi,
I've been looking everywhere to find an answer to this question, Basically, an equation is given
F(x)=3x(2-x)(x+1)(3+x)
What is the total local max and minimum value?
Please help me, my head is about to explode!! thank you!!
this is how my book defines it
local maximum -the point on a function that has the greatest y value on some interval close too the point
local minimum -the point on a function that has the least y value on some interval close too the point
I dont need to know the exact value but how many (i.e. 3 local min/max values or 2 local min/max) max and min!
sorry! my question shoould be how many local max/minimum
Nevermind I think I found the answer.
I think my question was unclear, im gonna try to clarify it. What Im trying to ask is how many local maximum or minimum (not the exact value), is in this function
F(x)=3x(2-x)(x+1)(3+x)
without graphing. From what I understand (n-1), where n is the degree of function is equal to the number of local maximum and local minimum. So in my equation the degree is 4, therefore the # of local max and min is 3, (4-1=3), correct answer. I think i got this right, unless someone thinks otherwise. But then I have another question, because i think this (n-1) doesnt apply to all functions. For instance
P(x)= X^6-16X^2+3
the # of local max and min is = 3, i thought it would be 5 (6-1). Please someone explain why its 3, without graphing?