okay so, obviously this is pretty urgent (due tomorrow) and i've been literally working on it all night, to no avail...
it's the integral of (sec(x))^5 dx
i have to do it using the integration by parts method
so far i have..
integral (sec(x))^5 dx= integral (sec(x))^3*(sec(x))^2 dx
then i tried to say that u=(sec(x))^3 and thus du= 3(sec(x))^2*(secxtanx) and dv= (sec(x))^2 dx so v= tan x
it gets really hairy from here..
i said tanxsec^3(x) - integral tanx*(3sec^3(x)tanx)dx
after that i got horribly confused.. this is due at 8:30 tomorrow morning, i'm so sorry to come off as someone putting this off until the last minute but i really have been trying to work on it
someone please help?