okay so, obviously this is pretty urgent (due tomorrow) and i've been literally working on it all night, to no avail...

it's the integral of (sec(x))^5 dx

i have to do it using the integration by parts method

so far i have..

integral (sec(x))^5 dx= integral (sec(x))^3*(sec(x))^2 dx

then i tried to say that u=(sec(x))^3 and thus du= 3(sec(x))^2*(secxtanx) and dv= (sec(x))^2 dx so v= tan x

it gets really hairy from here..

i said tanxsec^3(x) - integral tanx*(3sec^3(x)tanx)dx

after that i got horribly confused.. this is due at 8:30 tomorrow morning, i'm so sorry to come off as someone putting this off until the last minute but i really have been trying to work on it

someone please help?