Let u = sin(y) v = int.(sin(y)) dy = -cos(y) du = cos(y) dv = sin(y) uv - int. v du -Sin(y)cos(y) + int. (Cos(y))² dy Idk what to do =[
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No need for parts. Use the identity: $\displaystyle \sin^2{\theta} = \frac{1-\cos{2\theta}}{2}$
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