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Thread: Integration question

  1. February 24th 2009, 07:20 PM #1
    VkL
    VkL is offline
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    Integration question



    Let u = sin(y) v = int.(sin(y)) dy = -cos(y)
    du = cos(y) dv = sin(y)


    uv - int. v du

    -Sin(y)cos(y) + int. (Cos(y))² dy



    Idk what to do =[
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  2. February 24th 2009, 07:23 PM #2
    Chop Suey
    Chop Suey is offline
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    No need for parts. Use the identity:

    \sin^2{\theta} = \frac{1-\cos{2\theta}}{2}
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