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Math Help - partial derivatives (multivariable calc)

  1. #1
    Junior Member
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    Sep 2008
    Posts
    27

    partial derivatives (multivariable calc)

    z = f(xy)
    z/∂xz/∂y
    0
    1
    f '(x)
    f '(y)
    f '(xy)
    f '(x)f(y)
    f(x)f '(y)
    xf '(xy)
    yf '(xy)
    xyf '(xy)
    none of the above




    0
    1
    f '(x)
    f '(y)
    f '(xy)
    f '(x)f(y)
    f(x)f '(y)
    xf '(xy)
    yf '(xy)
    xyf '(xy)
    none of the above




    Any ideas??
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  2. #2
    Junior Member
    Joined
    Sep 2008
    Posts
    27
    My post is kind of confusing, all those f(x) and g(x) stuff under the z= are the multiple choice answers. There are 2 different questions, hence 2 different z =
    Also the first one is in terms of x, the second in terms of y.
    Thank You!!
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  3. #3
    Member
    Joined
    Sep 2006
    Posts
    77
    Well the derivative of f is f', and the chain rule states that we multiply f' by the derivative of the argument. So for the first one, we multiply by y and the second, by x giving

    a) yf '(xy)

    b) xf '(xy)
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