Find the length of the curve: x= (y^4)/4 + 1/(8y^2) from y=1 to y=2 I'm having trouble finding dx/dy
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Originally Posted by TAG16 Find the length of the curve: x= (y^4)/4 + 1/(8y^2) from y=1 to y=2 I'm having trouble finding dx/dy $\displaystyle y = \frac{1}{4}y^4 + \frac{1}{8}y^{-2}$ $\displaystyle \frac{dx}{dy} = y^3 - \frac{1}{4y^3}$ can you finish?
yeah, thats actually what I had I just didn't think I was right. thanks
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