try again ...
Determine the point(s) on the curve that correspond to the given slope of the tangent.
y = (2x-1)(-4+x^2), m=3
y' = 6x^2 - 2x - 8
Set y' = 3
3 = 6x^2 - 2x - 8
0 = 6x^2 - 2x - 5
Now what do I do. I used the quadratic formula to get x-intercepts:
[2+- sqrt(124)]/12
But these do not end up being the correct x values for the two points on this function??
Can someone help me, thanks.