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Math Help - Application Product Rule

  1. #1
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    Application Product Rule

    Determine the point(s) on the curve that correspond to the given slope of the tangent.

    y = (2x-1)(-4+x^2), m=3
    y' = 6x^2 - 2x - 8

    Set y' = 3
    3 = 6x^2 - 2x - 8
    0 = 6x^2 - 2x - 5

    Now what do I do. I used the quadratic formula to get x-intercepts:
    [2+- sqrt(124)]/12

    But these do not end up being the correct x values for the two points on this function??

    Can someone help me, thanks.
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  2. #2
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    6x^2 - 2x - 8 = 3

    6x^2 - 2x - 11 = 0

    try again ...
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