Why is U raised to the -1/5 here in the second step?

I understand that the 4/5 came from bringing u^1/5 up so that -1/5 + 1 = 4/5, but I do not see where the -1/5 comes from.

$\displaystyle \frac{1}{16}\int\frac{u-5}{u^{1/5}}du$

$\displaystyle \frac{1}{16}[u^{{4/5}} - 5u^{{-1/5}}]du$