Solve for x. $\displaystyle f(x)=log_3x+log_3(x-2)=1$
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Originally Posted by yeloc Solve for x. $\displaystyle f(x)=log_3x+log_3(x-2)=1$ what have you done? or based on your own notes, what can you do?
I don't know where to start. We reviewed logarithms before finding the derivatives of logarithms and this is the only question I have. Is there a way to simplify this first?
Originally Posted by yeloc I don't know where to start. We reviewed logarithms before finding the derivatives of logarithms and this is the only question I have. Is there a way to simplify this first? then $\displaystyle \log_a f(x) + \log_a g(x) = \log_a f(x)g(x)$ should be part of the review..
Thanks.
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