Solve for x.

$\displaystyle f(x)=log_3x+log_3(x-2)=1$

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- Feb 24th 2009, 04:50 AMyelocSolve for x using logarithms
Solve for x.

$\displaystyle f(x)=log_3x+log_3(x-2)=1$ - Feb 24th 2009, 04:57 AMkalagota
- Feb 24th 2009, 05:00 AMyeloc
I don't know where to start. We reviewed logarithms before finding the derivatives of logarithms and this is the only question I have.

Is there a way to simplify this first? - Feb 24th 2009, 05:03 AMkalagota
- Feb 24th 2009, 05:05 AMyeloc
Thanks.