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Math Help - Short Calculus Problem!

  1. #1
    Affinity
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    Smile Short Calculus Problem!

    Find the x-coordinates of all points on the curve y = (-x^2 + 4x - 3)^3 with a horizontal tangent line. (Thanks!)
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  2. #2
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    Quote Originally Posted by Affinity View Post
    Find the x-coordinates of all points on the curve y = (-x^2 + 4x - 3)^3 with a horizontal tangent line. (Thanks!)
    That is where,
    y'=0

    Thus, using the chain rule,
    3(-2x+4)(-x^2+4x-3)^2=0

    Thus,
    -2x+4=0 thus, x=2
    -x^2+4x-3=0 thus, x=1,3
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