R is the region that lies between the curve $\displaystyle y=\frac{1}{x^2+4x+5}$and the x-axis from x = -3 to x = -1. Find the area of R
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$\displaystyle \frac{1}{{x^2 + 4x + 5}} = \frac{1}{{\left( {x + 2} \right)^2 + 1}}$
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