# Thread: Help me !Parametric equation

1. ## Help me !Parametric equation

Eliminate the Parameter to find a Cartesian equation of the curve

a. $x=1+3t, y=2-t^{2}$
b. $x=4cos\theta , y =5sin\theta - \frac{\pi }{2}\leq 0\leq \frac{\pi }{2}$

2. Originally Posted by butbi9x
Eliminate the Parameter to find a Cartesian equation of the curve

a. $x=1+3t, y=2-t^{2}$
b. $x=4cos\theta , y =5sin\theta - \frac{\pi }{2}\leq 0\leq \frac{\pi }{2}$
a.

x^2 = 1 + 6t + t^2

so [-(x-1)^2]/9 + 2 = y

b. (x/4)^2 + (y/5)^2 = 1