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Math Help - Equation of tangent line to curve

  1. #1
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    Equation of tangent line to curve

    I need help solving these:

    y= tan (4x^2) at x0 = 0

    y= -ln(-x) at x0= -e

    ANY HELP WOULD BE AWESOME!
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  2. #2
    Senior Member mollymcf2009's Avatar
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    Quote Originally Posted by roksteady View Post
    I need help solving these:

    y= tan (4x^2) at x0 = 0

    y= -ln(-x) at x0= -e

    ANY HELP WOULD BE AWESOME!
    For both of these, you need to use the chain rule for your derivative. Then to find the value at x=0 and x=-e, just plug them into your derivative and solve for y. Then use your x & y values for your slope intercept equation of a line to find the equations for your lines.
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