I need help solving these:
$\displaystyle y= tan (4x^2) at x0 = 0$
y= -ln(-x) at x0= -e
ANY HELP WOULD BE AWESOME!
For both of these, you need to use the chain rule for your derivative. Then to find the value at x=0 and x=-e, just plug them into your derivative and solve for y. Then use your x & y values for your slope intercept equation of a line to find the equations for your lines.