find the average height of y=(2/3)*(sqrt (9 - x^2) ) over the interval [-3,3] i used the average height formula but i get the answer as 0 while the correct answer is supposed to be Pi/2 can someone help me out?
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how did you integrate to get to the last step? i think thats where im erring
you don't need calculus to integrate, only geometry ... the graph of from -3 to 3 is a semicircle of radius 3.
oh i see but is it possible to use calculus and find the area because thats what the question wants i think
possible, but a bit more involved. use the trig substitution
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