on int [0,1] Should I set u=arcsinx^2 and dv=x ??
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That is correct. You then need to use substitution on the second integral. Just ask if you get stuck.
start with ... now go with parts ... let and
u=arcsin(t) -> du= dv=dt -> v=t => (t)arcsin(t) - = ??? I'm getting lost here....
you are back-substituting too soon ... get the integral done completely in terms of t, then back substitute when finished. finish by back substituting for ...
where do you get the + 1/4 from???
the -2 is needed for the substitution required to find the antiderivative of the last integral expression.
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