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Math Help - another int. by parts (not a repost!)

  1. #1
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    another int. by parts (not a repost!)

    \int \frac{e^\frac{1}{t}}{t^2}dt

    u= e^{\frac{1}{t}}
    dv= t^{-2}

    Is the substitution right on this one?
    Sorry for asking some many of the same types of questions...
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  2. #2
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    Quote Originally Posted by saiyanmx89 View Post
    \int \frac{e^\frac{1}{t}}{t^2}dt

    u= e^{\frac{1}{t}}
    dv= t^{-2}

    Is the substitution right on this one?
    Sorry for asking some many of the same types of questions...
    It's not an integration by parts. if you make your substitution

     u = e^{\frac{1}{t}},\;\;\text{then}\;\; du = - \frac{1}{t^2} e^{\frac{1}{t}}\,dt and your integral becomes really simple.
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