$\displaystyle \int \frac{e^\frac{1}{t}}{t^2}dt$

u=$\displaystyle e^{\frac{1}{t}}$

dv=$\displaystyle t^{-2}$

Is the substitution right on this one?

Sorry for asking some many of the same types of questions...

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- Feb 22nd 2009, 02:42 PMsaiyanmx89another int. by parts (not a repost!)
$\displaystyle \int \frac{e^\frac{1}{t}}{t^2}dt$

u=$\displaystyle e^{\frac{1}{t}}$

dv=$\displaystyle t^{-2}$

Is the substitution right on this one?

Sorry for asking some many of the same types of questions... - Feb 22nd 2009, 02:48 PMJester