# another int. by parts (not a repost!)

• Feb 22nd 2009, 02:42 PM
saiyanmx89
another int. by parts (not a repost!)
$\int \frac{e^\frac{1}{t}}{t^2}dt$

u= $e^{\frac{1}{t}}$
dv= $t^{-2}$

Is the substitution right on this one?
Sorry for asking some many of the same types of questions...
• Feb 22nd 2009, 02:48 PM
Jester
Quote:

Originally Posted by saiyanmx89
$\int \frac{e^\frac{1}{t}}{t^2}dt$

u= $e^{\frac{1}{t}}$
dv= $t^{-2}$

Is the substitution right on this one?
Sorry for asking some many of the same types of questions...

It's not an integration by parts. if you make your substitution

$u = e^{\frac{1}{t}},\;\;\text{then}\;\; du = - \frac{1}{t^2} e^{\frac{1}{t}}\,dt$ and your integral becomes really simple.