Lagrange mulitplier problem

Yes, thanks for your quick reply.

I have f sub x as 2x - lambda 2x = 0

f sub z as 4z - lambda 2 z = 0

So I think since I get lambda = -y and also to 1 that y is -1 and since a squared is involved it could be 1 also. BUt when I plug these values in to original equation with x and z = to zero I get max of function at 2 and min at -2 whereas the answer says it should be 4 and -2

Can you advise as to my error???? FrostKing

Lagrange mulitplier problem comments

So in answer to your question from the fourth equation z = + or 1 0.866 since its square must be 0.75 so the equation is 1=1

And x = 0 for your second question, I think. I did not realize that lambda could be equal to one number and in the same set of equations that it was able to equal something else..Thanks much for your time! Frostking