Thread: Difficult Integral

Evaluate this integral:




Following an example in my texbook, I've split the top line:

I need a substitution where .
Hence .

Also, completing the square

So the integral can be written as:



I know I'll end up with an inverse trig function somewhere but that's where I get stuck.
Could someone please explain what to do. Thanks a lot.

Try something like

and then you can break it in two integrals and you will find a function