integral of 1/(9 + 4x^2)
The book says u should be 2/3x. Can someone enlighten me on why this is? I am dumbfounded
please be patient with me here as I still don't understand this. (2x/3)^2 x 9 would have to equal 4x^2 again here right? but wouldn't it be (18x/3)^2 = 6x^2?
edit: I guess because of the square, you simplify using square root or something. The calculator agrees with your result but somehow it still goes over my head