f(x)=(e^(squar root of x))*ln( (squar root of x ) +5 )
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Originally Posted by shannon1111 f(x)=(e^(squar root of x))*ln( (squar root of x ) +5 ) So here we are going to need a combination of the product rule and the chain rule. i.e the derivative of the first times the 2nd plut the 1st times the derivative of the 2nd. It just needs to be simplified from here
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