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Math Help - base integrations / evaluations (calc2)

  1. #1
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    base integrations / evaluations (calc2)

    Can someone please tell me if I am doing these right?

    (Just finding the anti-derivative)
    1. http://www.codecogs.com/eq.latex?\int_{}^{}\sin\left(8z-5\%20\right)
    My answer: -cos (4z^2-5z) (not sure if I have to follow the chain rule in this or not?) If not I think this is right.

    (Evaluation)
    2. http://www.codecogs.com/eq.latex?\int_{1}^{0}3x^{2}+x-5
    My answer: 3.5

    When I evaluated this I had
    -1 + -1/2 + 5

    (Evaluation)
    3. http://www.codecogs.com/eq.latex?\int_{-\sqrt[]{3}}^{\sqrt[]{3}}(t+1)(t^{2}+4)
    My answer: 29.32
    My anti-derivative: 1/4t^4 + 1/3t^3 + 2t^2 + 4t

    (Evaluation)
    4. http://www.codecogs.com/eq.latex?\int_{1/2}^{1}(1/u^{3}%20-%201/u^{4})
    My answer: .833
    Antiderivative: -1/2v^-2 - -1/3v^-3


    Am I doing these right at all?
    Last edited by joseph_; February 21st 2009 at 09:29 AM. Reason: (base was supposed to be "basic")
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  2. #2
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    Use preview before you post. I can't read it.
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  3. #3
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    Quote Originally Posted by joseph_ View Post
    Can someone please tell me if I am doing these right?

    (Just finding the anti-derivative)
    1.
    My answer: -cos (4z^2-5z) (not sure if I have to follow the chain rule in this or not?) If not I think this is right.

    (Evaluation)
    2.
    My answer: 3.5

    When I evaluated this I had
    -1 + -1/2 + 5

    (Evaluation)
    3.
    My answer: 29.32
    My anti-derivative: 1/4t^4 + 1/3t^3 + 2t^2 + 4t

    (Evaluation)
    4.
    My answer: .833
    Antiderivative: -1/2v^-2 - -1/3v^-3


    Am I doing these right at all?
    I put them into latex to make it more clear. (that's what you were talking about right?)
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