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Math Help - Integration by Parts?

  1. #1
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    Integration by Parts?

    Can someone explain this please?

    If \int udv = uv - \int vdu

    then how does



    I just don't see why the last part the 48cos(t/4), did not stay as the sine.
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  2. #2
    Moo
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    Quote Originally Posted by gammaman View Post
    Can someone explain this please?

    If \int udv = uv - \int vdu

    then how does



    I just don't see why the last part the 48cos(t/4), did not stay as the sine.
    Because \int \sin \frac t4 ~dt=-4 \cos \frac t4+c
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    Oh I see, because of the \int after the minus sign, I must still integrate and change the sine to cosine, right?
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    Quote Originally Posted by gammaman View Post
    Oh I see, because of the \int after the minus sign, I must still integrate and change the sine to cosine, right?
    Yes

    (I made a small typo, the integral of sine is -cosine)
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