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Math Help - Need help simplifying

  1. #1
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    Need help simplifying

    I'm trying to solve the Limit of x->-3, so I need help simplifying (-x^2+x+12)/(x+3)
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  2. #2
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    AFAIK, L'Hopital's rule can be applied here. That is: if \lim_{x \to c}\frac{f(x)}{g(x)}=\left ( \frac{0}{0} \right ) then \lim_{x \to c}\frac{f(x)}{g(x)}=\lim_{x \to c}\frac{f'(x)}{g'(x)}
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    Quote Originally Posted by giselled View Post
    I'm trying to solve the Limit of x->-3, so I need help simplifying (-x^2+x+12)/(x+3)
    \frac{-x^2+x+12}{x+3} = \frac{(x+3)(-x+4)}{(x+3)} = -x+4
    Last edited by mr fantastic; February 20th 2009 at 01:01 PM. Reason: Undeleted this reply (and an excellent reply it is too) since the OP probably does not know l'Hopital's Rule.
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  4. #4
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    Quote Originally Posted by giselled View Post
    I'm trying to solve the Limit of x->-3, so I need help simplifying (-x^2+x+12)/(x+3)
    Note that -x^2 + x + 12 = -(x^2 - x - 12) = -(x + 3)(x - 4).
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