# Need help simplifying

• February 20th 2009, 12:27 PM
giselled
Need help simplifying
I'm trying to solve the Limit of x->-3, so I need help simplifying (-x^2+x+12)/(x+3)
• February 20th 2009, 12:43 PM
Rist
AFAIK, L'Hopital's rule can be applied here. That is: if $\lim_{x \to c}\frac{f(x)}{g(x)}=\left ( \frac{0}{0} \right )$ then $\lim_{x \to c}\frac{f(x)}{g(x)}=\lim_{x \to c}\frac{f'(x)}{g'(x)}$
• February 20th 2009, 12:46 PM
Air
Quote:

Originally Posted by giselled
I'm trying to solve the Limit of x->-3, so I need help simplifying (-x^2+x+12)/(x+3)

$\frac{-x^2+x+12}{x+3} = \frac{(x+3)(-x+4)}{(x+3)} = -x+4$
• February 20th 2009, 12:58 PM
mr fantastic
Quote:

Originally Posted by giselled
I'm trying to solve the Limit of x->-3, so I need help simplifying (-x^2+x+12)/(x+3)

Note that $-x^2 + x + 12 = -(x^2 - x - 12) = -(x + 3)(x - 4)$.