i'm so sorry for keep asking questions but im really confused for this one.
the problem is y=(e^(x-1)*sin^2*x)/(((x^2)+5)^2x)
the trig function (sin^2 + 5), i don't know how to get a derivative out of that.
help me plz!
i'm so sorry for keep asking questions but im really confused for this one.
the problem is y=(e^(x-1)*sin^2*x)/(((x^2)+5)^2x)
the trig function (sin^2 + 5), i don't know how to get a derivative out of that.
help me plz!
Hi katieeej -
if you mean $\displaystyle \sin^2 x + 5 $ then this calls for a simple application of the chain rule for differentiation...
...where straight continuous line differentiate downwards with respect to x and the straight dashed line with respect to the dashed balloon expression, so that the triangular network satisfies the chain rule...
... though I'm not sure you meant \sin^2 x...
Don't integrate - balloontegrate!
Balloon Calculus: worked examples from past papers
the equation is
y=
e^(x-1)*sin^2(x)
-------------------- division
(x^2 +5)^2x
i started off like
ln y = ln(e^(x-1)sin^2 (x)) - ln (x^2 +5)^2x
= ln(e^(x-1))+ln (sin^2 (x))- 2x ln (x^2 +5)
= x-1 ln e +ln sin^2 (x) - 2x ln (x^2+5)
=x-1+ln (sin^2 (x)) -2x ln (x^2 +5)
then i don't know how to get derivatives.
And using the derivative of $\displaystyle \sin^2 x$ which is the same as that of $\displaystyle \sin^2 x + 5$ in the first picture...
Don't integrate - balloontegrate!
Balloon Calculus: worked examples from past papers