consider the function f(x) whose second derivative is f''(x) = 3x+2sin(x)

if f(0)=4, f'(x)=4. what is f(2) = ?

heres what i did

Printable View

- Nov 11th 2006, 09:17 PMvietintegral
consider the function f(x) whose second derivative is f''(x) = 3x+2sin(x)

if f(0)=4, f'(x)=4. what is f(2) = ?

heres what i did

- Nov 11th 2006, 09:54 PMsrinivas
i thik something is wrong how can a function which has sin o cos i it give the derivative as 4 that is a constant?

it ought to be a straight line for that - Nov 12th 2006, 12:14 AMCaptainBlack
- Nov 12th 2006, 12:19 AMCaptainBlack
- Nov 12th 2006, 07:14 AMSoroban
Hello, viet!

I agree with the Captain: there must be a typo in the problem.

I'll assume it is supposed to be:

Quote:

Consider the function whose second derivative is:

If , find

We have: .

Since , we have: .

. . Hence: .

We have: .

Since , we have: .

. . Hence: .

Therefore: . . . . etc.