How would i find the Maclaurin Series of f(x)=3^x or for that matter any basic number? I know its simaler to how e^x is found.
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$\displaystyle e^u = 1 + u + \frac{u^2}{2!} + \frac{u^3}{3!} + ...$ $\displaystyle 3^x = e^{\ln{3} \cdot x} = 1 + (\ln{3} \cdot x) + \frac{(\ln{3} \cdot x)^2}{2!} + \frac{(\ln{3} \cdot x)^3}{3!} + ...$
Thanks!
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