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Math Help - Area Enclosed

  1. #1
    Member
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    Area Enclosed

    Find the area of the enclosed region given by the functions:

    y = \frac{1}{x^2+1} and y = \frac{x^2}{2}

    I Got It Down To:
    A = \int_{-1}^{\frac{1}{2}} \left( (\sqrt{\frac{1-y}{y}}) - (\sqrt{2y}) \right) dy

    I Just Dont Know How To Integrate This Equation
    Thanks
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  2. #2
    MHF Contributor
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    Hi

    I am a little bit surprised by your answer



    A = \int_{-1}^{1} \left(\frac{1}{x^2+1} - \frac{x^2}{2}\right)\:dx
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  3. #3
    Member
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    haha i was integrating in terms of y
    thank you : )
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