Find the area of the enclosed region given by the functions:

$\displaystyle y = \frac{1}{x^2+1}$ and $\displaystyle y = \frac{x^2}{2}$

I Got It Down To:

$\displaystyle A = \int_{-1}^{\frac{1}{2}} \left( (\sqrt{\frac{1-y}{y}}) - (\sqrt{2y}) \right) dy$

I Just Dont Know How To Integrate This Equation

Thanks