# Area Enclosed

• Feb 19th 2009, 09:57 AM
qzno
Area Enclosed
Find the area of the enclosed region given by the functions:

$y = \frac{1}{x^2+1}$ and $y = \frac{x^2}{2}$

I Got It Down To:
$A = \int_{-1}^{\frac{1}{2}} \left( (\sqrt{\frac{1-y}{y}}) - (\sqrt{2y}) \right) dy$

I Just Dont Know How To Integrate This Equation
Thanks
• Feb 19th 2009, 10:17 AM
running-gag
Hi

I am a little bit surprised by your answer

http://nsa05.casimages.com/img/2009/...2055408371.jpg

$A = \int_{-1}^{1} \left(\frac{1}{x^2+1} - \frac{x^2}{2}\right)\:dx$
• Feb 19th 2009, 10:22 AM
qzno
haha i was integrating in terms of y
thank you : )