
Area Enclosed
Find the area of the enclosed region given by the functions:
$\displaystyle y = \frac{1}{x^2+1}$ and $\displaystyle y = \frac{x^2}{2}$
I Got It Down To:
$\displaystyle A = \int_{1}^{\frac{1}{2}} \left( (\sqrt{\frac{1y}{y}})  (\sqrt{2y}) \right) dy$
I Just Dont Know How To Integrate This Equation
Thanks

Hi
I am a little bit surprised by your answer
http://nsa05.casimages.com/img/2009/...2055408371.jpg
$\displaystyle A = \int_{1}^{1} \left(\frac{1}{x^2+1}  \frac{x^2}{2}\right)\:dx$

haha i was integrating in terms of y
thank you : )