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Math Help - comparison test

  1. #1
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    comparison test

    i think this function will diverge but i dont what g should equal.
    use comparsion test to show if function from 1 to infinitie x/(square root 1+ x^6) diverges or converges.
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  2. #2
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    Quote Originally Posted by twilightstr View Post
    i think this function will diverge but i dont what g should equal.
    use comparsion test to show if function from 1 to infinitie x/(square root 1+ x^6) diverges or converges.
    \frac{x}{\sqrt{1 + x^6}} < \frac{x}{\sqrt{x^6}} = \frac{x}{x^3} = \frac{1}{x^2}.

    So the series is convergent by the comparison test.
    Last edited by mr fantastic; February 19th 2009 at 02:24 AM. Reason: Fixed the inequality
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  3. #3
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    can g be 1/x if not, why not
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    Quote Originally Posted by twilightstr View Post
    can g be 1/x if not, why not
    No. Because the series is convergent.

    Re-read my first post. I have corrected my inequality.
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