Hi, Im having a problem finishing off a problem. It is a calc ab problem
A tank with a rectangular base and rectangular sides is to be open at the top. It is to be constructed so that its width is 4 meters and its volume is 36 cubic meters. If building the tank costs $10 per square meter for the base and 5$ for the sides, what is the cost of the least expensive tank?
So the information i gathered was:
S0 since V=LWH=36, 4LH=36, L=9/H
Then, SA= 36/h+18+8h
At first i thought I would just need to optimize that and go -36h^-2 + 8 and found the min was at 2.121 but then I thought you might need to factor in the price using another equation. Could someone help me with this problem?