i tried this: but when i got read of 2 roots i got another two roots which are more complicated ??
Last edited by transgalactic; Feb 18th 2009 at 09:07 AM.
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Originally Posted by transgalactic i tried this: but when i got read of 2 roots i got another two roots which are more complicated ?? Try
Hello, transgalactic! Danny has the best idea . . . Let: . . Then: . Substitute: . Long division: . Can you finish it now?
did i devided the polynomials correctly??
Originally Posted by transgalactic did i devided the polynomials correctly?? as Soroban did first factor out -6 then you'll have: u^2+1)=u^6-u^4-u^3+u^2+u-1-\frac{u-1}{u^2+1}" alt="(u^8-u^5)u^2+1)=u^6-u^4-u^3+u^2+u-1-\frac{u-1}{u^2+1}" />
i got a different remainder: -6u^6: 6u^4: 6u^3: -6u^2: -6u: 6\\
Put for the first integral, and which is very easy to integrate.
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