r = 1 + sin(theta) i know the integral equation should be: 1/2 integral pi/6 -> pi/2 ( 1 + sin(theta) + sin^2(theta) ) just need help solving through the integral please. thanks.
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Hello rcmango Originally Posted by rcmango r = 1 + sin(theta) i know the integral equation should be: 1/2 integral pi/6 -> pi/2 ( 1 + sin(theta) + sin^2(theta) ) just need help solving through the integral please. thanks. To integrate the term, use in the form and it's very straightforward from there. Grandad
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