The problem is integral of sin(x)/(1+x^2) from -1 to 1 I have tried integration by parts and substitution but it never seems to get any simpler. Any help would be appreciated. Thanks
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note that $\displaystyle \frac{\sin{x}}{1+x^2}$ is an odd function. so ... $\displaystyle \int_{-1}^1 \frac{\sin{x}}{1+x^2} \, dx = \, ?$
the integral of an odd function from -a to a is 0 ::smacks head against wall:: wow, that was really simple. thanks for the help though.
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