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Thread: Indefinite integral

  1. February 17th 2009, 03:37 PM #1
    Larrioto
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    Indefinite integral

    \int x^5(x^3+1)^{1/3}dx
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  2. February 17th 2009, 04:23 PM #2
    Scott H
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    Integrands with radicals can often be simplified by substituting u for the radical. This integral can be calculated by letting u=(x^3+1)^{\frac{1}{3}}.

    The next step is to cube both sides, u^3=x^3+1, and relate the differentials.
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