It's the integral from 1 to 10 of x divided by x^2-4. I'm assuming u would be x^2-4 making du 2x so du/2 would be x. Then would I just be left with 1/2 the integral of 1/u and would have to solve it from there?

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- February 17th 2009, 04:36 PMfattydqEvaluating this definite integral
It's the integral from 1 to 10 of x divided by x^2-4. I'm assuming u would be x^2-4 making du 2x so du/2 would be x. Then would I just be left with 1/2 the integral of 1/u and would have to solve it from there?

- February 17th 2009, 04:38 PMJester
- February 17th 2009, 04:41 PMfattydq
- February 17th 2009, 06:33 PMKrizalid
It must be a typo on the problem or those aren't the right bounds.

You're learning how to evaluate definite integrals, but you can't do this one because the function ain't continuous at Regarding those bounds, we have and belongs there.

If the question does not include the neither then you can evaluate the integral.