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Math Help - Integration with a 2 part du

  1. #1
    Junior Member
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    Jan 2009
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    Integration with a 2 part du

    Hi, I'm trying to solve this problem  (x^3+4x+3)x^2 dx but I'm having a lot of trouble since if I treat the bracketed part as 1 entity as I assumed I was supposed to, then I get a du value of 3x^2+4 which I can't figure out how to convert back to x^2 (i realize that it is likely very simple though).
    If I don't treat the bracketed part as 1 entity however, then I am unsure as to how to include the x^2dx part in my solution.
    Any help wold be appreciated.
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  2. #2
    Super Member
    Joined
    Jun 2008
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    Are you trying to integrate x^2(x^3+4x+3)?

    x^2(x^3+4x+3) = x^5 + 4x^3 + 3x^2

    And then apply power rule.
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  3. #3
    Junior Member
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    Jan 2009
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    gah, i knew i was missing something simple. Thanks for kickstarting my brain
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