# Math Help - Integration with a 2 part du

1. ## Integration with a 2 part du

Hi, I'm trying to solve this problem $(x^3+4x+3)x^2 dx$ but I'm having a lot of trouble since if I treat the bracketed part as 1 entity as I assumed I was supposed to, then I get a du value of $3x^2+4$ which I can't figure out how to convert back to $x^2$ (i realize that it is likely very simple though).
If I don't treat the bracketed part as 1 entity however, then I am unsure as to how to include the $x^2dx$ part in my solution.
Any help wold be appreciated.

2. Are you trying to integrate $x^2(x^3+4x+3)$?

$x^2(x^3+4x+3) = x^5 + 4x^3 + 3x^2$

And then apply power rule.

3. gah, i knew i was missing something simple. Thanks for kickstarting my brain