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- Feb 16th 2009, 06:47 PMyang03265Evaluate the integration by using integration by parts
- Feb 17th 2009, 06:55 AMred_dog
$\displaystyle \int\ln^3xdx=\int x'\ln^3xdx=x\ln^3x-\int x\cdot 3\ln^2x\cdot\frac{1}{x}dx=x\ln^3x-3\int\ln^2xdx$

Can you continue?