1.) Compute the following limit. The limit is approaching infinity. The equation is 5x+3 over 3x-2
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$\displaystyle \lim_{x\rightarrow\infty}\frac{5x+3}{3x-2} $ $\displaystyle =\lim_{x\rightarrow\infty}\frac{\frac{5x}{x}+\frac {3}{x}}{\frac{3x}{x}-\frac{2}{x}} $ Note that x approches infinity , 1/x approaches 0 .
Originally Posted by mathaddict $\displaystyle \lim_{x\rightarrow\infty}\frac{5x+3}{3x-2} $ $\displaystyle =\lim_{x\rightarrow\infty}\frac{\frac{5x}{x}+\frac {3}{x}}{\frac{3x}{x}-\frac{2}{x}} $ Note that x approches infinity , 1/x approaches 0 . You made a tiny error I believe. When writing everything over x, the 5x should be 5x^2 and the 3x should be 3x^2,but you don't need to write them like this to solve this limit which should be 5/3
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