Find the position of the particle:
a(t)=10+3t-3t^(2), s(0)=0, s(2)=10
Thanks for the help.
recall, $\displaystyle \int t^n~dt = \frac {t^{n + 1}}{n + 1} + C$, where C is a constant, and $\displaystyle n$ is a constant different from -1.
to get to $\displaystyle s(t)$, integrate $\displaystyle a(t)$ twice. use the data given for $\displaystyle s(t)$ to figure out the arbitrary constants