# Thread: Antiderivative question 2

1. ## Antiderivative question 2

Find the position of the particle:
a(t)=10+3t-3t^(2), s(0)=0, s(2)=10

Thanks for the help.

2. Originally Posted by nystudent2729
Find the position of the particle:
a(t)=10+3t-3t^(2), s(0)=0, s(2)=10

Thanks for the help.
recall, $\int t^n~dt = \frac {t^{n + 1}}{n + 1} + C$, where C is a constant, and $n$ is a constant different from -1.

to get to $s(t)$, integrate $a(t)$ twice. use the data given for $s(t)$ to figure out the arbitrary constants