Find an equation of the straight line that is tangent to the graph of f(x) root(x+1) and parallel to x - 6y+4 = 0. Find the slope of the tangent to the curve 1/x + 1/y = 1 at the point (2,2).
Follow Math Help Forum on Facebook and Google+
Originally Posted by mathamatics112 Find an equation of the straight line that is tangent to the graph of f(x) = root(x+1) and parallel to x - 6y+4 = 0. slope of tangent = f'(x) slope of tangent, which is parallel to line x - 6y+4 = 0 , is so, so, (8, 3) is the point on the curve where tangent is drawn. eqn of tangent y = mx + b so, eqn of tangent is
Last edited by Shyam; February 15th 2009 at 07:29 PM.
Originally Posted by mathamatics112 Find the slope of the tangent to the curve 1/x + 1/y = 1 at the point (2,2). differentiating wrt x, so, slope of tangent at (2, 2) is -1 eqn of tangent y = mx + b 2 = -1(2) + b b = 4 eqn of tangent is y = -x + 4
View Tag Cloud