x>0

for m i get:

m=lim |x-1| +1/x=infinity

x->infinity

so there is no vercital assimptote here?

Printable View

- February 15th 2009, 04:38 AMtransgalacticthe vertical assimptote of this function..
x>0

for m i get:

m=lim |x-1| +1/x=infinity

x->infinity

so there is no vercital assimptote here? - February 15th 2009, 04:49 AMearboth
- February 15th 2009, 05:01 AMtransgalactic
i agrre that there is an vertical assimptote here on x=0

is there any horisontal assimptote

i cant get the "m" value for it?

y=mx+n - February 15th 2009, 05:12 AMearboth
- February 15th 2009, 05:15 AMtransgalactic
there is a horisontal assmiptote y=mx+n

m=lim f(x)/x x->infinty

n=lim [f(x)-mx0] x->infinty

and my m limit is not defined so there is no horisontal assimptote

correct? - February 15th 2009, 05:36 AMearboth