Q: Find the area inside the region bounded by both r = sin theta and r = sin (2 theta)
I set the integral to.........
2[1/2{(sin 2x)^2 dx - 1/2{(sin2x)^2 - (sinx)^2 dx]
Notes: For efficiency, I used x for theta. Also, the limits of integration for each integral are from 0 to pi/3.
But my book says this, which doesn't make sense -
2[1/2{(sinx)^2 dx + 1/2{(sin2x)^2 dx]
Limits of integration for first integral: from 0 to pi/3
Limits of integration for second integral: from pi/3 to pi/2
Help please!
Cheers!