Thread: another differentiation

sorry to bother you alot

i tried to solve this one, but im not sure about my steps.

the problem is 1/csc(1-5x^2)

u=(1-5x^2)
f(u)=1/csc u im not sure if i can put it like this.

d/du*1/csc u * d/dx (1-5x^2)

thanks

the problem is 1/csc(1-5x^2)

u=(1-5x^2)
f(u)=1/csc u im not sure if i can put it like this.

$\displaystyle \frac{d}{dx}\frac{1}{csc~u} \times \frac{d}{dx} (1-5x^2)
$

I dont know what is "csc()" but it seems correct

Hello katieeej

Originally Posted by katieeej

sorry to bother you alot

i tried to solve this one, but im not sure about my steps.

the problem is 1/csc(1-5x^2)

u=(1-5x^2)
f(u)=1/csc u im not sure if i can put it like this.

d/du*1/csc u * d/dx (1-5x^2)

thanks

I assume that csc means 'cosec', in which case,

$\displaystyle \frac{1}{\csc (1-5x^2)}=\sin (1-5x^2)$

So its derivative is $\displaystyle -10x\cos(1-5x^2)$

Grandad