2. You can try , or maybe it would be more clear if you see it as .
3. Simply add 0 using 1. This is a basically a quick way around long division:
Thank you for replying.
the problem is
1- the integral is (sec^2 x +8secx cosx +16cos^x dx) so i was trying to find the relation or form of 16cos^2x in terms of the sec^2 x)
2-the integral of this question was (1/(sin^2x) - cosx/sin^2x )
3- i got the same result: integral 1+ 1/(x^2+1)
so im looking for the integral of 1/(x^+1)
THANK YOU AGAIN