Sorry it'd be (2h - h^2) on top wouldn't it? But that still doesn't work
Find the slope of the tangent line of the parabola 2x - x^2 at point (2,0):
So I have to use the forumla
m = lim f(a + h) - f(a) / h
h->0
So we have to find f(a) which = 0.
Then put in that to f(a + h) which = 2(0 + h) - (0+h)^2
So then you get for the equation:
(2h - 0) / h
Which would then equal 2, but the answer is -2...can anyone help?