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Math Help - [SOLVED] integrals

  1. #1
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    [SOLVED] integrals

    so we just learned integrals, and i'm having troubles solving this one:

    dy/dx = (2e^x + sec(x)tan(x) - x^(1/2))

    I've gotten to y= (2e^x)dx + sec(x) - (2/3)x^(3/2), but I can't figure out how to integrate 2e^x. please help?
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    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by jahichuanna View Post
    so we just learned integrals, and i'm having troubles solving this one:

    dy/dx = (2e^x + sec(x)tan(x) - x^(1/2))

    I've gotten to y= (2e^x)dx + sec(x) - (2/3)x^(3/2), but I can't figure out how to integrate 2e^x. please help?
    \int e^x\,dx=e^x+C...
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  3. #3
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    I get that part, but where did the 2 come from?
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    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by jahichuanna View Post
    I get that part, but where did the 2 come from?
    The 2 appears in the original problem.

    When you evaluate \int 2e^x\,dx, you can rewrite it by applying one of the integral properties. Its equivalent to 2\int e^x\,dx=2e^x+C

    Does this make sense?
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  5. #5
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    ah, ok. thanks.

    so the answer is 2e^x + sec x + (2/3)x^(3/2) + c?
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  6. #6
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by jahichuanna View Post
    ah, ok. thanks.

    so the answer is 2e^x + sec x + (2/3)x^(3/2) + c?
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