so we just learned integrals, and i'm having troubles solving this one:

dy/dx = (2e^x + sec(x)tan(x) - x^(1/2))

I've gotten to y= (2e^x)dx + sec(x) - (2/3)x^(3/2), but I can't figure out how to integrate 2e^x. please help?

Printable View

- February 12th 2009, 02:46 PMjahichuanna[SOLVED] integrals
so we just learned integrals, and i'm having troubles solving this one:

dy/dx = (2e^x + sec(x)tan(x) - x^(1/2))

I've gotten to y= (2e^x)dx + sec(x) - (2/3)x^(3/2), but I can't figure out how to integrate 2e^x. please help? - February 12th 2009, 02:49 PMChris L T521
- February 12th 2009, 02:50 PMjahichuanna
I get that part, but where did the 2 come from?

- February 12th 2009, 02:53 PMChris L T521
- February 12th 2009, 02:55 PMjahichuanna
ah, ok. thanks.

so the answer is 2e^x + sec x + (2/3)x^(3/2) + c? - February 12th 2009, 02:55 PMChris L T521