1. Finding this antiderivative

10(sin(2x)/sin(x))

I have no idea how to tackle something like this, could someone help me out?

2. Remember that $\displaystyle \sin 2x = 2\sin x \cos x$.

3. What? 2sin(x) does not equal 2sin(x)cos(x)

4. Originally Posted by fattydq
What? 2sin(x) does not equal 2sin(x)cos(x)
From trig, $\displaystyle \sin(2x)=2\sin x\cos x$

This is not the same as saying $\displaystyle 2\sin x$.

5. Ok wow, am I just supposed to know that? It seems to me like Calc II is just getting out of hand, like there's all these things we're just expected to know already that I've never even heard of, and I got an A+ in calc I.

6. Originally Posted by fattydq
Ok wow, am I just supposed to know that? It seems to me like Calc II is just getting out of hand, like there's all these things we're just expected to know already that I've never even heard of, and I got an A+ in calc I.
it's a trig identity...you should know more of them to become better with more problems. good luck in Calc II